github.com/deroproject/derosuite@v2.1.6-1.0.20200307070847-0f2e589c7a2b+incompatible/blockchain/median.go (about) 1 // Copyright 2017-2018 DERO Project. All rights reserved. 2 // Use of this source code in any form is governed by RESEARCH license. 3 // license can be found in the LICENSE file. 4 // GPG: 0F39 E425 8C65 3947 702A 8234 08B2 0360 A03A 9DE8 5 // 6 // 7 // THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS "AS IS" AND ANY 8 // EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES OF 9 // MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL 10 // THE COPYRIGHT HOLDER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, 11 // SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT LIMITED TO, 12 // PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS 13 // INTERRUPTION) HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, 14 // STRICT LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF 15 // THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE. 16 17 package blockchain 18 19 import "sort" 20 21 type uint64arr []uint64 22 23 func (a uint64arr) Len() int { return len(a) } 24 func (a uint64arr) Swap(i, j int) { a[i], a[j] = a[j], a[i] } 25 func (a uint64arr) Less(i, j int) bool { return a[i] < a[j] } 26 27 // Median gets the median number in a slice of uint64 numbers 28 // this function is used in so many checks that it should have unit tests for sure 29 // NOTE: it will the input array 30 31 func Median(inputs []uint64) (median uint64) { 32 33 // Start by sorting 34 sort.Sort(uint64arr(inputs)) 35 36 // No math is needed if there are no numbers 37 // For even numbers we add the two middle numbers 38 // and divide by two using the mean function above 39 // For odd numbers we just use the middle number 40 l := len(inputs) 41 if l == 0 { 42 return 0 43 } else if l%2 == 0 { 44 median = (inputs[(l/2)-1] + inputs[(l/2)]) / 2 45 } else { 46 median = inputs[l/2] 47 } 48 49 return median 50 }