github.com/googleapis/api-linter@v1.65.2/lint/rule_name.go (about) 1 // Copyright 2019 Google LLC 2 // 3 // Licensed under the Apache License, Version 2.0 (the "License"); 4 // you may not use this file except in compliance with the License. 5 // You may obtain a copy of the License at 6 // 7 // https://www.apache.org/licenses/LICENSE-2.0 8 // 9 // Unless required by applicable law or agreed to in writing, software 10 // distributed under the License is distributed on an "AS IS" BASIS, 11 // WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. 12 // See the License for the specific language governing permissions and 13 // limitations under the License. 14 15 package lint 16 17 import ( 18 "fmt" 19 "regexp" 20 "strings" 21 ) 22 23 // RuleName is an identifier for a rule. Allowed characters include a-z, 0-9, -. 24 // 25 // The namespace separator :: is allowed between RuleName segments 26 // (for example, my-namespace::my-rule). 27 type RuleName string 28 29 const nameSeparator string = "::" 30 31 var ruleNameValidator = regexp.MustCompile("^([a-z0-9][a-z0-9-]*(::[a-z0-9][a-z0-9-]*)?)+$") 32 33 // NewRuleName creates a RuleName from an AIP number and a unique name within 34 // that AIP. 35 func NewRuleName(aip int, name string) RuleName { 36 return RuleName(strings.Join([]string{ 37 getRuleGroup(aip, aipGroups), 38 fmt.Sprintf("%04d", aip), 39 name, 40 }, nameSeparator)) 41 } 42 43 // IsValid checks if a RuleName is syntactically valid. 44 func (r RuleName) IsValid() bool { 45 return r != "" && ruleNameValidator.Match([]byte(r)) 46 } 47 48 // HasPrefix returns true if r contains prefix as a namespace. prefix parameters can be "::" delimited 49 // or specified as independent parameters. 50 // For example: 51 // 52 // r := NewRuleName("foo", "bar", "baz") // string(r) == "foo::bar::baz" 53 // 54 // r.HasPrefix("foo::bar") == true 55 // r.HasPrefix("foo", "bar") == true 56 // r.HasPrefix("foo", "bar", "baz") == true // matches the entire string 57 // r.HasPrefix("foo", "ba") == false // prefix must end on a delimiter 58 func (r RuleName) HasPrefix(prefix ...string) bool { 59 s := strings.Join(prefix, nameSeparator) 60 return string(r) == s || strings.HasPrefix(string(r), s+nameSeparator) 61 }