github.com/keysonZZZ/kmg@v0.0.0-20151121023212-05317bfd7d39/kmgRpc/kmgRpcJava/java/src/com/google/gson/JsonDeserializer.java (about) 1 /* 2 * Copyright (C) 2008 Google Inc. 3 * 4 * Licensed under the Apache License, Version 2.0 (the "License"); 5 * you may not use this file except in compliance with the License. 6 * You may obtain a copy of the License at 7 * 8 * http://www.apache.org/licenses/LICENSE-2.0 9 * 10 * Unless required by applicable law or agreed to in writing, software 11 * distributed under the License is distributed on an "AS IS" BASIS, 12 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. 13 * See the License for the specific language governing permissions and 14 * limitations under the License. 15 */ 16 17 package com.google.gson; 18 19 import java.lang.reflect.Type; 20 21 /** 22 * <p>Interface representing a custom deserializer for Json. You should write a custom 23 * deserializer, if you are not happy with the default deserialization done by Gson. You will 24 * also need to register this deserializer through 25 * {@link GsonBuilder#registerTypeAdapter(Type, Object)}.</p> 26 * 27 * <p>Let us look at example where defining a deserializer will be useful. The {@code Id} class 28 * defined below has two fields: {@code clazz} and {@code value}.</p> 29 * 30 * <pre> 31 * public class Id<T> { 32 * private final Class<T> clazz; 33 * private final long value; 34 * public Id(Class<T> clazz, long value) { 35 * this.clazz = clazz; 36 * this.value = value; 37 * } 38 * public long getValue() { 39 * return value; 40 * } 41 * } 42 * </pre> 43 * 44 * <p>The default deserialization of {@code Id(com.foo.MyObject.class, 20L)} will require the 45 * Json string to be <code>{"clazz":com.foo.MyObject,"value":20}</code>. Suppose, you already know 46 * the type of the field that the {@code Id} will be deserialized into, and hence just want to 47 * deserialize it from a Json string {@code 20}. You can achieve that by writing a custom 48 * deserializer:</p> 49 * 50 * <pre> 51 * class IdDeserializer implements JsonDeserializer<Id>() { 52 * public Id deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context) 53 * throws JsonParseException { 54 * return new Id((Class)typeOfT, id.getValue()); 55 * } 56 * </pre> 57 * 58 * <p>You will also need to register {@code IdDeserializer} with Gson as follows:</p> 59 * 60 * <pre> 61 * Gson gson = new GsonBuilder().registerTypeAdapter(Id.class, new IdDeserializer()).create(); 62 * </pre> 63 * 64 * <p>New applications should prefer {@link TypeAdapter}, whose streaming API 65 * is more efficient than this interface's tree API. 66 * 67 * @author Inderjeet Singh 68 * @author Joel Leitch 69 * 70 * @param <T> type for which the deserializer is being registered. It is possible that a 71 * deserializer may be asked to deserialize a specific generic type of the T. 72 */ 73 public interface JsonDeserializer<T> { 74 75 /** 76 * Gson invokes this call-back method during deserialization when it encounters a field of the 77 * specified type. 78 * <p>In the implementation of this call-back method, you should consider invoking 79 * {@link JsonDeserializationContext#deserialize(JsonElement, Type)} method to create objects 80 * for any non-trivial field of the returned object. However, you should never invoke it on the 81 * the same type passing {@code json} since that will cause an infinite loop (Gson will call your 82 * call-back method again). 83 * 84 * @param json The Json data being deserialized 85 * @param typeOfT The type of the Object to deserialize to 86 * @return a deserialized object of the specified type typeOfT which is a subclass of {@code T} 87 * @throws JsonParseException if json is not in the expected format of {@code typeofT} 88 */ 89 public T deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context) 90 throws JsonParseException; 91 }