modernc.org/ccgo/v3@v3.16.14/lib/testdata/CompCert-3.6/test/c/perlin.c (about) 1 // perlin noise, derived from the Java reference implementation at 2 // http://mrl.nyu.edu/~perlin/noise/ 3 4 #include <math.h> 5 #include <stdio.h> 6 7 static int p[512]; 8 9 static int permutation[256] = { 151,160,137,91,90,15, 10 131,13,201,95,96,53,194,233,7,225,140,36,103,30,69,142,8,99,37,240,21,10,23, 11 190, 6,148,247,120,234,75,0,26,197,62,94,252,219,203,117,35,11,32,57,177,33, 12 88,237,149,56,87,174,20,125,136,171,168, 68,175,74,165,71,134,139,48,27,166, 13 77,146,158,231,83,111,229,122,60,211,133,230,220,105,92,41,55,46,245,40,244, 14 102,143,54, 65,25,63,161, 1,216,80,73,209,76,132,187,208, 89,18,169,200,196, 15 135,130,116,188,159,86,164,100,109,198,173,186, 3,64,52,217,226,250,124,123, 16 5,202,38,147,118,126,255,82,85,212,207,206,59,227,47,16,58,17,182,189,28,42, 17 223,183,170,213,119,248,152, 2,44,154,163, 70,221,153,101,155,167, 43,172,9, 18 129,22,39,253, 19,98,108,110,79,113,224,232,178,185, 112,104,218,246,97,228, 19 251,34,242,193,238,210,144,12,191,179,162,241, 81,51,145,235,249,14,239,107, 20 49,192,214, 31,181,199,106,157,184, 84,204,176,115,121,50,45,127, 4,150,254, 21 138,236,205,93,222,114,67,29,24,72,243,141,128,195,78,66,215,61,156,180 22 }; 23 24 static inline double fade(double t) 25 { return t * t * t * (t * (t * 6 - 15) + 10); } 26 27 static inline double lerp(double t, double a, double b) 28 { return a + t * (b - a); } 29 30 static double grad(int hash, double x, double y, double z) { 31 int h = hash & 15; // CONVERT LO 4 BITS OF HASH CODE 32 double u = h<8 ? x : y, // INTO 12 GRADIENT DIRECTIONS. 33 v = h<4 ? y : h==12||h==14 ? x : z; 34 return ((h&1) == 0 ? u : -u) + ((h&2) == 0 ? v : -v); 35 } 36 37 static double noise(double x, double y, double z) { 38 int X = (int)floor(x) & 255, // FIND UNIT CUBE THAT 39 Y = (int)floor(y) & 255, // CONTAINS POINT. 40 Z = (int)floor(z) & 255; 41 x -= floor(x); // FIND RELATIVE X,Y,Z 42 y -= floor(y); // OF POINT IN CUBE. 43 z -= floor(z); 44 double u = fade(x), // COMPUTE FADE CURVES 45 v = fade(y), // FOR EACH OF X,Y,Z. 46 w = fade(z); 47 int A = p[X ]+Y, AA = p[A]+Z, AB = p[A+1]+Z, // HASH COORDINATES OF 48 B = p[X+1]+Y, BA = p[B]+Z, BB = p[B+1]+Z; // THE 8 CUBE CORNERS, 49 50 return lerp(w, lerp(v, lerp(u, grad(p[AA ], x , y , z ), // AND ADD 51 grad(p[BA ], x-1, y , z )), // BLENDED 52 lerp(u, grad(p[AB ], x , y-1, z ), // RESULTS 53 grad(p[BB ], x-1, y-1, z ))),// FROM 8 54 lerp(v, lerp(u, grad(p[AA+1], x , y , z-1 ), // CORNERS 55 grad(p[BA+1], x-1, y , z-1 )), // OF CUBE 56 lerp(u, grad(p[AB+1], x , y-1, z-1 ), 57 grad(p[BB+1], x-1, y-1, z-1 )))); 58 } 59 60 static void init(void) { 61 int i = 0; 62 for (i=0; i < 256 ; i++) 63 p[256+i] = p[i] = permutation[i]; 64 } 65 66 int main(int argc, char ** argv) { 67 init(); 68 69 double x, y, z, sum = 0.0; 70 for (x = -5.0; x < 5.0; x += 0.1) 71 for (y = -5.0; y < 5.0; y += 0.1) 72 for (z = -5.0; z < 5.0; z += 0.1) 73 sum += noise(x, y, z); 74 75 printf("%.4e\n", sum); 76 return 0; 77 }